(3^x)(4^2x+1)=6^x+2

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Solution for (3^x)(4^2x+1)=6^x+2 equation: 



(3^x)(4^2x+1)=6^x+2

We move all terms to the left:

(3^x)(4^2x+1)-(6^x+2)=0

We get rid of parentheses

3^x(4^2x+1)-6^x-2=0

We move all terms containing x to the left, all other terms to the right

3^x(4^2x+1)-6^x=2

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